find-all query

[cormullion]

With find-all, how do I specify an option without specifying an expression:

(find-all str-pattern str-text [expr] [int-option])

I want to find all the valid numbers in a string, so want to specify some options such as case-insensitive... But I don't want to process anything...

[Sammo]

How about something like

> (find-all "(is)" "newLISPisNEWLISP" $1 1)
("IS" "is" "IS")

in which [expr] = $1.

[cormullion]

Right. Although it seems like the $1 is just a filler, until you need the option...

Code: Select all

> (find-all "is" "newLISP is cool, is it")
("is" "is")
> (find-all "is" "newLISP is cool, is it" $1 0)
("is" "is")
> (find-all "is" "newLISP is cool, is it" $1 1)
("is" "is" "is")

[/code]

[Lutz]

... or if there are no parenthesized sub-expressions:

Code: Select all

(find-all "is" "newLISPisNEWLISP" $0 1)
=> ("IS" "is" "IS")

$0 is always the entire expression found, without any processing.

Lutz

[cormullion]

OK, thanks!