Embedded lists with match?

[methodic]

Is something like this possible:

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(set 'lst '("key ("this one" "that one" "other one")))
(match '(? ("that one")) lst)

Basically I need to go backwards in referencing the key with one of it's elements.

Thanks in advance!

[cormullion]

Possibly:

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> (match '(? (* "that one" *)) lst)
;-> ("key" ("this one") ("other one"))

[Lutz]

... and this same pattern would work for the others too, as the * star stands for 0, 1 or more:

Code: Select all

(match '(? (* "this one" *)) lst)
(match '(? (* "other one" *)) lst)