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With the DUP function if I write

(dup '(2 3) 3) this is ((2 3)(2 3)(2 3))

but what if I want (2 3 2 3 2 3) ?

I could write (flat (dup '(2 3) 3)) but that is a little cumbersome. Could the DUP function be modified so that I could write (dup 2 3 3) where it is understood that multiple previous arguments are duplicated in order?

Will this work? > (DUP 1 2 3)
(1 2 1 2 1 2)
> (DUP 1 10)
(1 1 1 1 1 1 1 1 1 1)
> (DUP '(1 2) 10)
(1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2)
> (DUP '(1 2) "A" 5)
(1 2 "A" 1 2 "A" 1 2 "A" 1 2 "A" 1 2 "A")
> (DUP 5)
()

Or this? > (DUP 1 2 3)
(1 2 1 2 1 2)
> (DUP 1 10)
(1 1 1 1 1 1 1 1 1 1)
> (DUP '(1 2) 10)
((1 2) (1 2) (1 2) (1 2) (1 2) (1 2) (1 2) (1 2) (1 2) (1 2))
> (DUP '(1 2) "A" 5)
((1 2) "A" (1 2) "A" (1 2) "A" (1 2) "A" (1 2) "A")
> (DUP 5)
()