For the Compleat Fan
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alex
- Posts: 100
- Joined: Thu Mar 10, 2005 2:27 pm
- Location: Russia
Post
by alex »
(pretty-int)
I wrote useful function(IMHO)
Code: Select all
;; Transform integer to special string format(see example)
;;
;; syntax: (pretty-int num)
;; syntax: (pretty-int num delimiter)
;;
;; Example:
;; (pretty-int 20482048) -> "20 482 048"
;; (pretty-int 1234567890 "'") -> "1'234'567'890"
;;
(define (pretty-int num delimiter)
(unless delimiter (setq delimiter " "))
(trim (reverse (replace {(\d{3})} (reverse (string num)) (append $1 delimiter) 0)) delimiter)
)
Can anybody propose more simple or useful variant?
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Sammo
- Posts: 180
- Joined: Sat Dec 06, 2003 6:11 pm
- Location: Loveland, Colorado USA
Post
by Sammo »
Hello Alex,
Nice work. Here's another solution that uses a regular expression I found in RegexBuddy's (
http://www.regexbuddy.com/) library.
Code: Select all
(define (pretty-int num delim)
(let
( pattern "(?<=[0-9])(?=(?:[0-9]{3})+(?![0-9]))" )
;body of let
(replace pattern (string num) (or delim " ") 0) ))
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Dmi
- Posts: 408
- Joined: Sat Jun 04, 2005 4:16 pm
- Location: Russia
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Contact:
Post
by Dmi »
I usins such one:
Code: Select all
(define (format-sum a)
(let (s (format "%18.2f" a) r "")
(dotimes (i 5)
(set 'r (append r " " ((* 3 i) 3 s))))
(append r (-3 s))))
not much elegant, but quite nice for finacial reports...
WBR, Dmi