Hi Lutz,
when I save with 'save this is the result in that file ->
(set 'data '(49 79 45 76 64 58 4e 79 4c 32 4a 70 62 69 39 75 5a 58 64 73 61 58 4e
77 43 6a 73 37 49 47 56 34 59 57 31 77 62 47 55 67 64 47 56 34 64 41 6f 6f 63 48
4a 70 62 6e 52 73 62 69 41 69 58 47 35 63 63 6c 52 49 53 56 4d 67 53 56 4d 67 52
56 68 46 51 31 56 55 52 55 51 67 52 6c 4a 50 54 53 42 58 53 56 52 49 53 55 34 67
54 6b 56 58 54 45 6c 54 55 43 46 63 62 6c 78 79 49 69 6b 4b 4b 47 56 34 61 58 51
70 43 67 3d 3d))
If I then go on the newlisp prompt and do ->
>(load "test")
Then this is the output -->
> (load "test")
true
> data
(49 79 45 76 64 58 4 e 79 4 c 32 4 a 70 62 69 39 75 5 a 58 64 73
61 58 4 e 77 43 6 a 73 37 49 47 56 34 59 57 31 77 62 47 55 67 64
47 56 34 64 41 6 f 6 f 63 48 4 a 70 62 6 e 52 73 62 69 41 69 58
47 35 63 63 6 c 52 49 53 56 4 d 67 53 56 4 d 67 52 56 68 46 51 31
56 55 52 55 51 67 52 6 c 4 a 50 54 53 42 58 53 56 52 49 53 55 34
67 54 6 b 56 58 54 45 6 c 54 55 43 46 63 62 6 c 78 79 49 69 6 b
4 b 4 b 47 56 34 61 58 51 70 43 67 3 d 3 d)
Do you see the difference? 'Load does manipulate the data list !!
How come? I thought it was a one on one copy?
Regards, Norman...
save versus load
save versus load
-- (define? (Cornflakes))
another example ->
--- file t1 contains this ->
(set 'a '( 1a 1b 1c 1d 1e 1f ))
(set 'b '( aa bb cc dd ee ff ))
(set 'c '( a1 b1 c1 d1 e1 f1 ))
(set 'd '( 1A 1B 1C 1D 1E 1F ))
> (load "t1")
true
> a
(1 a 1 b 1 c 1 d 1 e 1 f)
> b
(aa bb cc dd ee ff)
> c
(a1 b1 c1 d1 e1 f1)
> d
(1 A 1 B 1 C 1 D 1 E 1 F)
>
This means i can never use HEX numbers in a list and 'load it...
So it seems that LOAD does eveluate because its not a string that
is inside the list. Oke fine.. But how to bypass this? Its much more
work to (read-file t1) evaluate it and but it inside to code.. thats why
i tried 'load.. Mmmmmmm
--- file t1 contains this ->
(set 'a '( 1a 1b 1c 1d 1e 1f ))
(set 'b '( aa bb cc dd ee ff ))
(set 'c '( a1 b1 c1 d1 e1 f1 ))
(set 'd '( 1A 1B 1C 1D 1E 1F ))
> (load "t1")
true
> a
(1 a 1 b 1 c 1 d 1 e 1 f)
> b
(aa bb cc dd ee ff)
> c
(a1 b1 c1 d1 e1 f1)
> d
(1 A 1 B 1 C 1 D 1 E 1 F)
>
This means i can never use HEX numbers in a list and 'load it...
So it seems that LOAD does eveluate because its not a string that
is inside the list. Oke fine.. But how to bypass this? Its much more
work to (read-file t1) evaluate it and but it inside to code.. thats why
i tried 'load.. Mmmmmmm
-- (define? (Cornflakes))
1a 3b etc will be parsed as 1 a 3 b etc. thats just how the syntax parse rules work.
Do your (set 'data '(...)) in an intecative window to see:
Instead put this in your file, when you deal with hex values
Lutz
Do your (set 'data '(...)) in an intecative window to see:
Code: Select all
> (set 'data '(3a 4b 8f))
(3 a 4 b 8 f)
>
Code: Select all
(set 'data '(0x3a 0x4b 0x8f))