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anti-select elements of a list

Posted: Fri Dec 21, 2018 2:18 am
by lyl
The function "select" can be used to select multi-elements of a list at one time, for example:

Code: Select all

(select '(0 1 2 3 4) '(1 2)) 
->(1 2)

Yet what I want is to get all elements other than those "selceted", that is to say, I want to obtain (0 3 4) from above example.
I tried with the function "filter" like this:

Code: Select all

(filter (not (find $idx '(1 2))) '(0 1 2 3 4))
but it fails because "filter" does not support $idx.

So, is there a better way to anti-select elements in a list at one time by another list which assign positions those elements to be deleted?

Re: anti-select elements of a list

Posted: Fri Dec 21, 2018 10:37 am
by newBert
Here is a solution (probably not the only one, nor the best) :

Code: Select all

newLISP v.10.7.5 64-bit on Linux IPv4/6 UTF-8 libffi, options: newlisp -h

> (select '(0 1 2 3 4) (difference (index true? '(0 1 2 3 4)) '(1 2)))
(0 3 4)
> ;; maybe clearer:
>
(let (lst '(0 1 2 3 4))
  (select lst (difference (index true? lst) '(1 2))))

(0 3 4)
>

Re: anti-select elements of a list

Posted: Fri Dec 21, 2018 2:45 pm
by lyl
newBert wrote:Here is a solution (probably not the only one, nor the best) :

Code: Select all

newLISP v.10.7.5 64-bit on Linux IPv4/6 UTF-8 libffi, options: newlisp -h

> (select '(0 1 2 3 4) (difference (index true? '(0 1 2 3 4)) '(1 2)))
(0 3 4)
> ;; maybe clearer:
>
(let (lst '(0 1 2 3 4))
  (select lst (difference (index true? lst) '(1 2))))

(0 3 4)
>
If the lst contains nil(0 1 2 3 nil), how to do?

Re: anti-select elements of a list

Posted: Fri Dec 21, 2018 4:23 pm
by fdb

Code: Select all

(define (unselect lst sel)
  (clean (fn(x) (member x sel)) lst))

(unselect '( 0 1 2 3 nil) '(1 2))

(0 3 nil)

Re: anti-select elements of a list

Posted: Fri Dec 21, 2018 4:39 pm
by fdb
or just

Code: Select all

(difference '(0 1 2 3 nil) '(1 2))

(0 3 nil)
or am I misunderstanding something?

Re: anti-select elements of a list

Posted: Sat Dec 22, 2018 1:18 am
by lyl
@fdb '(1 2) in my example means the position of elements in lst, not elements themselves. I think I give a poor example.

Re: anti-select elements of a list

Posted: Sat Dec 22, 2018 4:21 am
by ralph.ronnquist
So you might be looking for something like the following:

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(define (drop lst idx) (let (n -1) (clean (fn (x) (member (inc n) idx)) lst)))

> (drop '(5 4 3 2 1) '(1 2))
(5 2 1)

Re: anti-select elements of a list

Posted: Sat Dec 22, 2018 12:36 pm
by newBert
lyl wrote:
newBert wrote:Here is a solution (probably not the only one, nor the best) :

Code: Select all

newLISP v.10.7.5 64-bit on Linux IPv4/6 UTF-8 libffi, options: newlisp -h

> (select '(0 1 2 3 4) (difference (index true? '(0 1 2 3 4)) '(1 2)))
(0 3 4)
> ;; maybe clearer:
>
(let (lst '(0 1 2 3 4))
  (select lst (difference (index true? lst) '(1 2))))

(0 3 4)
>
If the lst contains nil(0 1 2 3 nil), how to do?
I replaced 0 1 2 3 4... with a b c d e... for clarity.

Code: Select all

>
(let (lst '(a b c d nil f))
  (select lst (difference (sequence 0 (- (length lst) 1)) '(1 2))))

(a d nil f)
>

Re: anti-select elements of a list

Posted: Sat Dec 22, 2018 12:38 pm
by fdb
or use select and the difference of the selected indexes:

Code: Select all

(define (unselect lst sel)
	 (select lst (difference (sequence 0 (dec (length lst))) sel)))

> (unselect '(5 4 3 2 1) '(1 2))
(5 2 1)

Re: anti-select elements of a list

Posted: Sat Dec 22, 2018 12:43 pm
by lyl
Many thanks all of you for these beautiful solutions!!