newlispfanclub.alh.net

Posted: **Thu Nov 27, 2014 12:47 pm**

I recently met a "problem"

I wrote a newlisp file ,let's say, test1.lsp

then I want the test1.lsp to deal with files in the (main-args) , like

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newlisp test1.lsp xxxx.file

In my mind, I thought newlisp and test1.lsp are together like one binary file
but then I found out , the command "newlisp" will also try to run xxxx.file whatever it is,just a file

I think there is no method can stop this behavior ,right?

so maybe newlisp can have a command line argument,like -f ? to seprate the files need to be executed or just use them as "string argments" ?

Posted: **Thu Nov 27, 2014 4:08 pm**

Just add the (exit) command to the end of your test1.lsp file to prevent the further loading of files as code...

This feature is so that any modules (that don't have the exit command) can be loaded ahead of your final code file...

-- xytroxon

Posted: **Fri Nov 28, 2014 2:04 am**

I generally just use the #! syntax

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$ cat foo.lsp
#!/usr/bin/newlisp

(println (main-args))
(exit)

$ chmod 755 foo.lsp    # make sure foo.lsp is executable
$ ./foo.lsp xxxx.file
("/usr/bin/newlisp" "./foo.lsp" "xxxx.file")

Hope this helps.

.. m.

Posted: **Mon Dec 01, 2014 3:49 am**

Oh yeah

Thanks to you all, it works now

:)

Posted: **Mon Dec 01, 2014 9:37 pm**

Use (reset) at the end of the script rather than (exit) If you want to enter interactive mode at that point.

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