newlispfanclub.alh.net

Posted: **Tue Dec 25, 2012 8:31 am**

Hi guys

in newlisp docs

(format "%e" 123456789)        → "1.234568e+08"

But when I reverse this

Code: Select all

> (int 1.234568e+08)
123456800

Got the different results
Why is this happend?

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newLISP v.10.4.4 on OSX IPv4/6. 64bits

Posted: **Tue Dec 25, 2012 9:32 am**

Code: Select all

> (format "%e" 123456789)
"1.234568e+008"
> (format "%.6e" 123456789)
"1.234568e+008"
> (int 1.234568e+008)
123456800
> (format "%.7e" 123456789)
"1.2345679e+008"
> (int 1.2345679e+008)
123456790
> (format "%.8e" 123456789)
"1.23456789e+008"
> (int 1.23456789e+008)
123456789

Please read format.

Posted: **Tue Dec 25, 2012 9:51 am**

Code: Select all

(format "%e" 123456789)

Without precision parameter it uses a default precision, so t gets rounded.
(Not mentioned in the doc)

Posted: **Tue Dec 25, 2012 1:24 pm**

oh God

thanks guys

newlispfanclub.alh.net

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