newlispfanclub.alh.net

Posted: **Mon Sep 10, 2012 2:02 pm**

> (setf str {abc1111abc222})
"abc1111abc222"
> (replace {a(bc)} str (push  $1 lst -1) 0)
"abc1111abc222"
;why ?
;(push  $1 lst -1)  will return lst then  lst replace {a(bc)}    ???
;
> (setf lst nil)
nil
> (replace {a(bc)} str (println (push  $1 lst -1)) 0)
("bc")
("bc" "bc")
"abc1111abc222"

> (replace {a(bc)} str $1  0)
"bc1111bc222"

Posted: **Tue Sep 11, 2012 10:14 pm**

I think it's because your first replace expression is trying to replace the found string with a list:

If all arguments are strings, replace replaces all occurrences of str-key in str-data with the evaluated exp-replacement, returning the changed string. (newLISP Reference Manual)

So this won't do anything:

Code: Select all

(replace "(a)bc" "abcabc" (list $1) 0)
;-> abcabc

whereas this will:

Code: Select all

(replace "(a)bc" "abcabc" (upper-case $1) 0)
;-> AA

Posted: **Wed Sep 12, 2012 3:53 pm**

OMG

If all arguments are strings

include exp-replacement evaluated !!!!!!

newlispfanclub.alh.net

confused by replace ?

confused by replace ?

Re: confused by replace ?

Re: confused by replace ?