newlispfanclub.alh.net

Posted: **Wed Apr 18, 2012 3:10 am**

This is code:

(setq mylst '(nil nil nil nil nil nil nil nil nil nil nil nil))
(dolist (item mylst) (println (length item)))

Why the result is:

3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3
3

Posted: **Wed Apr 18, 2012 3:35 am**

Because (length 'nil) is 3.

On the other hand, (length nil) is 0.

Posted: **Wed Apr 18, 2012 3:45 am**

Length applied to a symbol returns the length of the symbol name:

http://www.newlisp.org/downloads/newlis ... tml#length

Posted: **Wed Apr 18, 2012 4:37 am**

OK, thx.
The difference with common lisp is: In common lisp the (length 'nil) is zero, and in newlisp is the symbols length.

The length of nil value