newlispfanclub.alh.net

Posted: **Wed Dec 16, 2009 6:27 pm**

Is something like this possible:

(set 'lst '("key ("this one" "that one" "other one")))
(match '(? ("that one")) lst)

Basically I need to go backwards in referencing the key with one of it's elements.

Thanks in advance!

Posted: **Wed Dec 16, 2009 7:52 pm**

Possibly:

> (match '(? (* "that one" *)) lst)
;-> ("key" ("this one") ("other one"))

Posted: **Thu Dec 17, 2009 8:15 am**

... and this same pattern would work for the others too, as the * star stands for 0, 1 or more:

(match '(? (* "this one" *)) lst)
(match '(? (* "other one" *)) lst)

Embedded lists with match?