speed on default functor
Posted: Thu Nov 27, 2008 9:29 pm
Hi lutz,
-> (setq biglist:biglist '( a b c d e ... ... ... ))
(a b c d e ... ... ...)
-> (setq referer biglist)
biglist
->
Do i understand it correclty that when it now comes to speed on this "list"
working on the 'referer results in speed performance? Or can i now also work
on the functor biglist, because its a functor?
(So actualy the 'referer is a pointer based list?)
-> (setq biglist:biglist '( a b c d e ... ... ... ))
(a b c d e ... ... ...)
-> (setq referer biglist)
biglist
->
Do i understand it correclty that when it now comes to speed on this "list"
working on the 'referer results in speed performance? Or can i now also work
on the functor biglist, because its a functor?
(So actualy the 'referer is a pointer based list?)