Code: Select all
(setq mytable (list (list (char "a") "a: choiceA" '(+ 0 101)) (list (char "b") "b: choiceB" '(+ 0 102))))Search found 1 match
- Sat Jun 29, 2019 8:31 am
- Forum: newLISP in the real world
- Topic: How to partially evaluate elements in a hash-table
- Replies: 5
- Views: 4835
Re: How to partially evaluate elements in a hash-table
This can be one way of doing it. The quote function can also be used if the list is being built at runtime.